A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of 2 
in earth’s horizontal magnetic field of 24 microtesla. When a horizontal field of 18 microtesla is produced opposite to the earth’s field by placing a current carrying wire, the new time period of magnet will be
Text Solution
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The time period 
of oscillation of a magnet is given by
where,
Moment of inertia of the magnet about the axis of rotation
Magnetic moment of the magnet
Uniform magnetic field
As 
remains the same
or 
According to given problem,
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